Array of pointer

-
int main( )
{
int *p,i;

int val[7] = { 11, 22, 33, 44, 55, 66, 77 } ;


p = &val[0];

for ( i = 0 ; i <= 6 ; i++ )
{
printf("\n value is %d ",*p);
p++;
}
return 0;
}

Comments

  1. Unknown1:45 PM

    #include
    #include
    void main()
    {
    int a[5]={5,10,15,20,25};
    int i;
    int*ptr;
    ptr=&a[0];
    clrscr();
    for(i=0;i<=4;i++)
    {
    printf("\n \t %d is stored at %u",*ptr,ptr);
    ptr++;
    }
    getch();
    }

    ReplyDelete
  2. Anonymous2:27 PM

    U R SCHOLER.....

    ReplyDelete
  3. Unknown3:52 PM

    /*Program To Demonstrate Array of pointer*/

    #include

    void main()
    {
    int a[5]={5,10,15,20,25};
    int i;
    int*ptr;
    ptr=&a[0];
    clrscr();
    for(i=0;i<=4;i++)
    {
    printf("\n \t %d is stored at %u",*ptr,ptr);
    ptr++;
    }
    getch();
    }

    ReplyDelete
  4. Swati Waghmare11:15 AM

    /*Demonstrate array of pointer*/
    #include
    void main()
    {
    char *name[5]={"sweeti","aishu","dipu","mayu","divu"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("\n\t%d name is %s",i,name[i]);
    }
    }

    ReplyDelete
  5. poonam pusavale11:20 AM

    /*array of pointer*/
    #include
    void main()
    {
    char name[3][6]={"skn","scoe","korti"};
    int i=0;
    for(i=0;i<=2;i++)
    {
    printf("\n\t %s",name[i]);
    }
    }

    ReplyDelete
  6. Pandhare Dipali11:35 AM

    /*Demonstrate array of pointer*/
    #include
    void main()
    {
    char *name[5]={"sweeti","aishu","dipu","mayu","divu"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("\n\t%d name is %s",i,name[i]);
    }
    }

    ReplyDelete
  7. Bhanvase Yashoda12:06 PM

    /*Array of pointer*/
    #include
    void main()
    {
    int i=0;
    char*a={"goa","punjab","maharastra"};

    for(i=0;i<=2;i++)
    {
    printf("%d state is%s",i,a[i]);

    }

    }

    ReplyDelete
  8. Bhanvase Yashoda12:08 PM

    /*Array of pointer*/
    #include
    void main()
    {
    int i=0;
    char*a[3]={"goa","punjab","maharastra"};

    for(i=0;i<=2;i++)
    {
    printf("%d state is%s",i,a[i]);

    }

    }

    ReplyDelete
  9. sachita jadhav12:15 PM

    /* array & pointer */
    #include
    void main()
    {
    int a[5]={1,2,3,4,5};
    int i;
    int * p1;
    p1=&a[0];
    for(i=0;i<=4;i++)
    {
    printf("\n %d is stored at %u",*p1,p1);
    p1++;
    }
    }

    ReplyDelete
  10. sushma jadhav12:16 PM

    /*Demonstrate array of pointer*/
    #include
    void main()
    {
    char *name[5]={"ram","sham","ashu"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("\n\t%d name is %s",i,name[i]);
    }
    }

    ReplyDelete
  11. sayali daunde12:24 PM

    /* array & pointer */
    #include
    void main()
    {
    int a[5]={1,2,3,4,5};
    int i;
    int * p1;
    p1=&a[0];
    for(i=0;i<=4;i++)
    {
    printf("\n %d is stored at %u",*p1,p1);
    p1++;
    }
    }

    ReplyDelete
  12. Dipali Kore12:28 PM

    /*Demonstrate array of pointer*/
    #include
    void main()
    {
    char *name[5]={"skn","scoe","korti","ppur","slpr"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("\n\t%d name is %s",i,name[i]);
    }
    }

    ReplyDelete
  13. puja khandare12:30 PM

    #include
    void main()
    {
    int i=0;
    char*a[3]={"pooja","pallavi","amar"};

    for(i=0;i<=2;i++)
    {
    printf("%d state is%s",i,a[i]);

    }

    }

    ReplyDelete
  14. sonali nagane11:30 AM

    /* array & pointer */
    #include
    void main()
    {
    int a[5]={1,2,3,4,5};
    int i;
    int * p1;
    p1=&a[0];
    for(i=0;i<=4;i++)
    {
    printf("\n %d is stored at %u",*p1,p1);
    p1++;
    }
    }

    ReplyDelete
  15. wadegaonkar aishwarya11:40 AM


    /*Demonstrate array of pointer*/
    #include
    void main()
    {
    char *name[5]={"sweeti","aishu","dipu","mayu","divu"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("\n\t%d name is %s",i,name[i]);
    }
    }

    ReplyDelete
  16. mubin pirjade11:44 AM

    int main( )
    {
    int *p,i;

    int val[7] = { 11, 22, 33, 44, 55, 66, 77 } ;


    p = &val[0];

    for ( i = 0 ; i <= 6 ; i++ )
    {
    printf("\n value is %d ",*p);
    p++;
    }
    return 0;
    }

    ReplyDelete
  17. Akshay Sidwadkar12:15 PM

    int main( )
    {
    int *p,i;

    int val[7] = { 11, 22, 33, 44, 55, 66, 77 } ;


    p = &val[0];

    for ( i = 0 ; i <= 6 ; i++ )
    {
    printf("\n value is %d ",*p);
    p++;
    }
    return 0;
    }

    ReplyDelete

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