25. Write a program to demonstrate the use of pointer to pointer


Comments

  1. #include

    int main () {

    int a;
    int *ptr;
    int **pptr;

    a = 3000;


    ptr = &a;


    pptr = &ptr;


    printf("Value of var = %d\n", a );
    printf("Value available at *ptr = %d\n", *ptr );
    printf("Value available at **pptr = %d\n", **pptr);

    return 0;
    }

    ReplyDelete
  2. #include
    void main()
    {
    int i=2,*j,**k;
    j=&i;
    printf("value of j= %d",*j);
    k=&j;
    printf("\n Value of K=%d\n",**k);
    }

    ReplyDelete
  3. Mubin Pirjade12:54 PM

    hi,there!!
    #include
    void main()
    {
    int a=125;
    int *j,**k;
    j=&a;
    k=&j;
    printf("\n\tValue of a=%d",a);
    printf("\n\tValue of a=%d",*j);
    printf("\n\tvalue of a=%d",**k);
    printf("\n\tAddress of a=%u",&a);
    printf("\n\tAddress of a=%u",j);
    printf("\n\taddress of j=%u",&j);
    printf("\n\taddress of j=%u",k);
    }

    ReplyDelete
  4. Waghmare Swati1:32 PM

    /*Demonstrate the use of pointer to pointer*/
    #include
    void main()
    {
    int i=2,*j,**k;
    j=&i;
    k=&j;
    {
    printf("value of j= %d",*j);
    }
    {
    printf("\n Value of K=%d\n",**k);
    }
    }

    ReplyDelete
  5. Pandhare Dipali1:34 PM

    #include
    void main()
    {
    int a=248;
    int *j,**k;
    j=&a;
    k=&j;
    printf("\n\t value of a=%d",a);
    printf("\n\t value of a=%d",*j);
    printf("\n\t value of a=%d",**k);
    printf("\n\t address of a=%u",&a);
    printf("\n\t address of a=%u",j);
    printf("\n\t address of a=%u",&j);
    printf("\n\t address of a=%u ",k);
    }

    ReplyDelete
  6. lengarepooja3:47 PM

    #include
    void main()
    {
    int a=12;
    int *j,**k;
    j=&a;
    k=&j;
    printf("\n\tValue of a=%d",a);
    printf("\n\tValue of a=%d",*j);
    printf("\n\tvalue of a=%d",**k);

    }

    ReplyDelete
  7. /*pointer to pointer*/
    #include
    void main()
    {
    int i=2,*j,**k;
    j=&i;
    printf("value of j= %d",*j);
    k=&j;
    printf("\n Value of K=%d\n",**k);
    }

    ReplyDelete
  8. lengarepooja5:07 PM

    #include
    void main()
    {

    int i=10;
    int*j;
    j=&i;
    int **k;
    k = &j;
    printf("\nAddress of i = %u",&i);
    printf("\nAddress of i = %u",j);
    printf("\nAddress of i = %u",*k);
    printf("\nAddress of j = %u",&j);
    printf("\nAddress of j = %u",k);
    printf("\nAddress of k = %u",&k);
    printf("\nValue of j = %u",j);
    printf("\nValue of k = %u",k);
    printf("\nValue of i = %d",i);
    printf("\nValue of i = %d",*(&i));
    printf("\nValue of i = %d",*j);
    printf("\nValue of i = %d",**k);

    }

    ReplyDelete
  9. Sayali Daunde12:15 PM

    // Demonstration pointer to pointer
    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\nvalue of i=%d",i);
    printf("\nvalue of i=%d",*&i);


    printf("\nvalue of i=%d",**k);


    }

    ReplyDelete
  10. sushma jadhav12:28 PM

    //Demonstrate the use of pointer to pointer
    #include
    void main()
    {
    int i=200,*j,**k;
    j=&i;
    k=&j;

    printf("value of j= %d",*j);

    printf("\n Value of K=%d\n",**k);

    }

    ReplyDelete
  11. #include
    void main()
    {
    int a=10;
    int *p,**q;
    p=&a;
    q=&p;
    printf("value of a=%d\n",a);
    printf("value of a=%d\n",*p);
    printf("value of a=%d\n",**q);
    printf("Address of a=%u\n",&a);
    printf("Address of p=%u\n",&p);
    printf("Address of q=%u\n",&q);
    }

    ReplyDelete
  12. Dipali Kore12:32 PM

    // Demonstration pointer to pointer
    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\nvalue of i=%d",i);
    printf("\nvalue of i=%d",*&i);


    printf("\nvalue of i=%d",**k);


    }

    ReplyDelete
  13. Radha Ghadge SE 238:42 AM

    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\n value of i=%d",i);
    printf("\n value of i=%d",&i);
    printf("\n value of j=%u",&i);
    printf("\n value of k=%u",&j);
    printf("\n value of i=%d",**k);
    }

    ReplyDelete
  14. Bhosale Dhanashri SE38:59 AM

    / Demonstration pointer to pointer
    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\nvalue of i=%d",i);
    printf("\nvalue of i=%d",*&i);


    printf("\nvalue of i=%d",**k);


    }

    ReplyDelete
  15. poonam pusavale9:14 AM

    /*pointer to pointer*/
    #include
    void main()
    {
    int i=2;
    int *j;
    int **k;
    j=&i;
    k=&j;
    {
    printf("\n\t value of j=%d",*j);
    }
    {
    printf("\n\t value of k=%d\n",**k);

    }
    }

    ReplyDelete
  16. //Use of pointer to pointer
    #include
    void main()
    {
    int a=11;
    int *p,**k;
    p=&a;
    k=&p;
    printf("value of a=%d \t",a);
    printf("value of a=%d \t",*p);
    printf("value of a=%d \t",**k);
    printf("Address of a=%u \t",&a);
    printf("Address of p=%u \t",&p);
    printf("Address of k=%u \n",&k);
    }

    ReplyDelete
  17. Bhosale Dhanashri SE39:22 AM

    // Demonstration pointer to pointer
    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\nvalue of i=%d",i);
    printf("\nvalue of i=%d",*&i);


    printf("\nvalue of i=%d",**k);


    }

    ReplyDelete
  18. puja khandare9:36 AM

    #include
    void main()
    {
    int i=2,*j,**k;
    j=&i;
    k=&j;
    {
    printf("value of j= %d",*j);
    }
    {
    printf("\n Value of K=%d\n",**k);
    }
    }

    ReplyDelete
  19. sonali nagane9:41 AM

    #include
    void main()
    {
    int i=2,*j,**k;
    j=&i;
    k=&j;
    {
    printf("\n value of j=%d",*j);
    }
    {
    printf("\n value of k=%d",**k);
    }
    }

    ReplyDelete
  20. Bhanvase Yashoda10:11 AM

    /* demonstration pointer to pointer */
    #include
    void main()
    {
    int i=2;
    int*j;
    int**k;
    j=&i;
    k=&j;
    printf("i=%d",i);
    printf("j=%u",&i);
    printf("k=%u",&j);
    printf("i=%d",**k);
    }

    ReplyDelete
  21. Ranjit kalubarme12:07 PM

    #include
    void main()
    {
    int a=11;
    int *p,**k;
    p=&a;
    k=&p;
    printf("value of a=%d \t",a);
    printf("value of a=%d \t",*p);
    printf("value of a=%d \t",**k);
    printf("Address of a=%u \t",&a);
    printf("Address of p=%u \t",&p);
    printf("Address of k=%u \n",&k);
    }

    ReplyDelete
  22. Bhosale Dhanashri SE312:12 PM

    #include
    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\n\t value of i=%d",*(&i));

    printf("\n\t address of i=%u",&i);
    printf("\n\t value of j=%u",&i);

    printf("\n\t address of j=%u",&j);
    printf("\n\t value of k=%u",&j);
    printf("\n\t address of k=%u",&k);
    printf("\n\t value of i=%d",**k);


    }

    ReplyDelete
  23. Awate Snehal11:09 AM

    /*Demonstrate the use of pointer to pointer*/
    #include
    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\n\t value of i=%d",*(&i));

    printf("\n\t address of i=%u",&i);
    printf("\n\t value of j=%u",&i);

    printf("\n\t address of j=%u",&j);
    printf("\n\t value of k=%u",&j);
    printf("\n\t address of k=%u",&k);
    printf("\n\t value of i=%d",**k);


    }

    ReplyDelete
  24. sachita jadhav11:28 AM

    #include
    void main()
    {
    int i=2;
    int *j;
    j=&i;
    int **k;
    k=&j;
    printf("\n value of i=%d",i);
    printf("\n address of i=%u",j);
    printf("\n value of j=%u",*(&j));
    printf("\n address of j=%u",k);
    printf("\n value of k=%u",*(&k));
    printf("\n address of k=%u",&k);
    printf("\n value of i=%d",**k);
    }

    ReplyDelete

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