36. Multiplication of two number using pointer.


Comments

  1. Swati Waghmare11:43 AM

    /*Multiplication of number using pointer*/
    #include
    void main()
    {
    int a,b,*ptr1,*ptr2;
    ptr1=&a;
    ptr2=&b;
    printf("\n\tEnter two numbers");
    scanf("%d%d",&a,&b);
    printf("MULTUPLICATION=%d",(*ptr1)*(*ptr2));
    }

    ReplyDelete
  2. Pandhare Dipali11:48 AM

    /*multiplication of two no.s using pointer*/
    #include
    void main()
    {
    int *ptr1,*ptr2,i,j;
    ptr1=&i;
    ptr2=&j;
    printf("\n\t Enter two no.s");
    scanf("%d%d",&i,&j);
    (*ptr1)*(*ptr2);
    *(&i)*(&j);
    ptintf("\n\t multiplication=%d",(*&i)*(*&j));
    }

    ReplyDelete
  3. poonam pusavale11:49 AM

    /*mul of num using pointer*/
    #include
    void main()
    {
    int a,b;
    int *ptr1,*ptr2;
    ptr1=&a;
    ptr2=&b;
    printf("\n\t enter two number");
    scanf("%d %d",&a,&b);
    printf("\n\tmultiplication=%d",(*ptr1)*(*ptr2));
    }

    ReplyDelete
  4. sayali daunde11:54 AM

    #include
    void main()
    {

    int a,b;
    int *ptr1=&a;
    int *ptr2=&b;

    ptr1=&a;
    ptr2=&b;

    printf("\nEnter the two number for multipilaction using Pointer=");
    scanf("%d %d",&a,&b);

    printf("Multiplication using pointers=%d",(*ptr1)*(*ptr2));
    }

    ReplyDelete
  5. Mane Yogesh12:07 PM

    #include
    void main()
    {
    int a,b;
    int *ptr1, *ptr2;
    ptr1=&a;
    ptr2=&b;

    printf(" \n\t enter the two number=");
    scanf("%d%d",&a,&b);

    printf("\n\t multi=%d",(*ptr1)*(*ptr2));
    }

    ReplyDelete
  6. // Multiplication by using pointer
    #include
    #include
    void main()
    {
    int a=5,b=6;
    int *p,*q;
    p=&a;
    q=&b;
    printf("\t Multiplication of two no.=--%d \n",(*p)*(*q));
    }

    ReplyDelete
  7. Dipali Kore12:17 PM

    /* Program to perform Multiplication using Pointer */

    #include
    void main()
    {

    int a,b;
    int *ptr1;
    int *ptr2;

    ptr1=&a;
    ptr2=&b;

    printf("\nEnter the two numbers.....");
    scanf("%d %d",&a,&b);

    printf("MULTIPLICATION=%d",(*ptr1)*(*ptr2));
    }

    ReplyDelete
  8. Bhosale Dhanashri SE312:28 PM

    #include
    void main()
    {
    int a ,b;
    int *p1;
    p1=&a;
    int *p2;
    p2=&b;
    printf("\n\t Enter the two number==");
    scanf("%d%d",&a,&b);
    printf("\n\t Multiplication of two numbers=%d",(*p1)*(*p2));

    }

    ReplyDelete
  9. Bhanvase Yashoda11:05 AM

    /*pointer to pointer display content*/
    #include
    void main()
    {
    char str[10]="sknscoe";
    int*p;
    p=&str[0];
    while(*p[i]|=NULL)
    {i++;
    p++;

    }
    printf("\n\t legth=%d",i);

    }










    ReplyDelete
  10. sachita jadhav11:07 AM

    /* multiplication of pointer */
    #include
    void main()
    {
    int a,b;
    int *p1,*p2;
    p1=&a;
    p2=&b;
    printf("enter 1st no.");
    scanf("%d",&a);
    printf(" enter 2nd no.");
    printf("\n multiplication=%d",(*p1)*(*p2));
    }

    ReplyDelete
  11. mubin pirjade11:10 AM

    #include
    void main()
    {
    int *ptr1,*ptr2;
    int a,b;
    ptr1=&a;
    ptr2=&b;
    printf("\n\tEnter two numbers:");
    scanf("%d%d",&a,&b);
    printf("\n\tMultiplication=%d",(*ptr1)*(*ptr2));
    }

    ReplyDelete
  12. Bhanvase Yashoda11:21 AM

    /*pointer multiplication*/
    #include
    void main()
    {
    int*p1,*p2;
    int a,b;
    p1=&a;
    p2=&b;
    printf("\n\tEnter two no.");
    scanf("%d,%d",&a,&b);
    printf("mul=%d",(*p1)*(*p2));
    }







    ReplyDelete
  13. Awate Snehal12:13 PM

    /*Multiplication of 2 no using pointer*/
    #include
    void main()
    {
    int a,b;
    int *p1,*p2;
    p1=&a;
    p2=&b;
    printf("\n enter 2 number");
    scanf("%d%d",&a,&b);
    printf("\n multipliction=%d",(*p1)*(*p2));
    }

    ReplyDelete
  14. sonali nagane11:12 AM

    /*Multiplication of number using pointer*/
    #include
    void main()
    {
    int a,b,*ptr1,*ptr2;
    ptr1=&a;
    ptr2=&b;
    printf("\n\tEnter two numbers");
    scanf("%d%d",&a,&b);
    printf("MULTUPLICATION=%d",(*ptr1)*(*ptr2));
    }

    ReplyDelete

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