39. Program to demonstrate Array of pointer.

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Comments

  1. Swati Waghmare12:28 PM

    /*Demonstrate array of pointer*/
    #include
    void main()
    {
    char *name[5]={"sweeti","aishu","dipu","mayu","divu"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("\n\t%d name is %s",i,name[i]);
    }
    }

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  2. poonam pusavale12:28 PM

    /*array of ptr*/
    #include
    void main()
    {
    char *name[3]={"poonam" "dipali" "vaishali"};
    int i=0;
    for(i=0;i<=2;i++)
    {
    printf("%d name is %s",i,name[i]);
    }
    }

    ReplyDelete
  3. Dipali Kore12:39 PM

    //array of pointer
    #include
    void main()
    {
    char *state[5]={"panjab",
    "maharashtra",
    "dehli",
    "karnataka",
    "bihar"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("%d state is %s",i,state[i]);
    }
    }

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  4. sachita jadhav11:02 AM

    /* array & pointer */
    #include
    void main()
    {
    int a[5]={1,2,3,4,5};
    int i;
    int * p1;
    p1=&a[0];
    for(i=0;i<=4;i++)
    {
    printf("\n %d is stored at %u",*p1,p1);
    p1++;
    }
    }

    ReplyDelete
  5. sayali daunde11:13 AM

    //array of pointer
    #include

    void main()
    {
    char *state[5]={"panjab",
    "maharashtra",
    "dehli",
    "karnataka",
    "bihar"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("%d state is %s",i,state[i]);
    }
    }

    ReplyDelete
  6. mubin pirjade11:13 AM

    //array of pointer
    #include
    void main()
    {
    char *state[5]={"panjab",
    "maharashtra",
    "dehli",
    "karnataka",
    "bihar"};
    int i=0;
    for(i=0;i<=4;i++)
    {
    printf("%d state is %s",i,state[i]);
    }
    }

    ReplyDelete
  7. sonali nagane11:22 AM

    /* array & pointer */
    #include
    void main()
    {
    int a[5]={1,2,3,4,5};
    int i;
    int * p1;
    p1=&a[0];
    for(i=0;i<=4;i++)
    {
    printf("\n %d is stored at %u",*p1,p1);
    p1++;
    }
    }

    ReplyDelete

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